# Dank n Edgy

The dorkest, edgist forums known to puny hoomans

You are not logged in.

## Announcement

Welcome to DnE, the online psych facility. (Run by the inmates, for the inmates.)

## #1 2012-06-14 12:11:49

lamefun
Member
Registered: 2012-06-12
Posts: 148

### Disproof of geometry and complex numbers

Lets consider a nail with a hole in it (1). Since complex numbers are unambiguously defined by two real numbers and so are points in a plane, consider lets an intersection of a complex plane with the nail (2). It's obvious that for every part of the space inside the nail there exists ? = Vair / Vnail, where Vnail is the volume of the nail in that part of the space and Vair is the volume of the air in that part of the space. But now consider (3), where the part of the space (green) is clearly inside the nail, but Vnail = 0, so as x/0 = ? there must be infinite air but this can't be. Q.E.D.

Last edited by lamefun (2012-06-14 13:20:02)

Offline

## #2 2012-06-15 03:23:08

loon_attic
Banned
Registered: 2012-06-08
Posts: 10,259

### Re: Disproof of geometry and complex numbers

I think that's like saying that derivatives don't exist because with the formula f'(x) =  lim a->x [f(a)-f(x)]/[a-x], the "denominator" looks like zero... but then there isn't really any INSTANTANEOUS slope for a certain point in the function... but there is... or better yet, that vertical lines don't exist because their slope has a zero on the denominator.

sloth wrote:

Comfy does not provide challenge, challenge provides success, success provides happiness. Our world is not comfy, although we tried to make it so. Slaves of our own inventions, yada, yada. Not only on a technological level, also on a social and political level. Nothing more but apes. Apes with psychosomatic disorders.

Offline

## Board footer

Powered by FluxBB